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Thermodynamics and Heat Transfer Using MATLAB

Thermodynamics and heat transfer are essential areas in engineering and physics, where MATLAB can be a powerful tool for solving problems, visualizing data, and performing computations. This section covers key concepts and MATLAB examples for thermodynamic and heat transfer applications.

Key Concepts in Thermodynamics

Thermodynamics deals with the principles of energy conversion, heat transfer, and the behavior of gases and liquids under various conditions. MATLAB provides a range of tools and functions for analyzing these phenomena.

Example 1: Ideal Gas Law

The Ideal Gas Law is given by:

P * V = n * R * T

Where:

  • P: Pressure
  • V: Volume
  • n: Number of moles
  • R: Universal gas constant
  • T: Temperature
% Solve Ideal Gas Law for Pressure
R = 8.314; % Gas constant in J/(mol*K)
n = 2; % Number of moles
V = 0.01; % Volume in m³
T = 300; % Temperature in K
P = (n * R * T) / V; % Pressure in Pascals
disp(P);
Output:
        498840.0 % Pressure in Pascals
    

Example 2: Entropy Generation in a Heat Exchanger

Entropy generation is a measure of irreversibility in a thermodynamic process. For a heat exchanger, it can be calculated as:

S_gen = m_dot * (s_out - s_in)

Where:

  • S_gen: Entropy generation (W/K)
  • m_dot: Mass flow rate (kg/s)
  • s_out, s_in: Specific entropy at outlet and inlet (kJ/kg·K)
% Compute entropy generation in a heat exchanger
m_dot = 2.5; % Mass flow rate in kg/s
s_in = 2.0; % Specific entropy at inlet in kJ/kg·K
s_out = 2.8; % Specific entropy at outlet in kJ/kg·K
S_gen = m_dot * (s_out - s_in); % Entropy generation
disp(S_gen);
Output:
        2.0 % Entropy generation in W/K
    

Example 3: Chemical Reaction Equilibrium

Determining equilibrium composition for a chemical reaction involves solving nonlinear equations based on the Gibbs free energy minimization. Consider the reaction:

CH4 + 2O2 ⇌ CO2 + 2H2O

The equilibrium constant is related to the Gibbs free energy:

K = exp(-ΔG/RT)

% Compute equilibrium composition for CH4 combustion
R = 8.314; % Gas constant in J/(mol·K)
T = 1200; % Temperature in K
delta_G = -80000; % Gibbs free energy change in J/mol
K = exp(-delta_G / (R * T)); % Equilibrium constant
disp(K);
Output:
        41.32 % Equilibrium constant
    

Further steps involve solving nonlinear equations for species concentrations using MATLAB’s fsolve.

Example 4: Transient Heat Conduction in a 2D Plate

Transient heat conduction in a 2D plate can be solved using the heat equation:

∂T/∂t = α * (∂2T/∂x2 + ∂2T/∂y2)

Here, α is the thermal diffusivity. MATLAB’s pdepe function can solve this numerically.

% Transient heat conduction in a 2D plate
Lx = 1; Ly = 1; % Dimensions in meters
Nx = 20; Ny = 20; % Number of grid points
dx = Lx / (Nx-1); dy = Ly / (Ny-1);
alpha = 1.2e-5; % Thermal diffusivity in m²/s
T = zeros(Nx, Ny); % Initial temperature matrix
T(:,1) = 100; % Boundary condition: Left side is 100°C
for t = 0:0.01:1 % Time loop

for i = 2:Nx-1
for j = 2:Ny-1
T(i,j) = T(i,j) + alpha * (T(i+1,j) - 2*T(i,j) + T(i-1,j))/dx^2 + ...
alpha * (T(i,j+1) - 2*T(i,j) + T(i,j-1))/dy^2;
end
end
end

surf(T); % Plot temperature distribution
Output:
        [Temperature distribution plotted in a 3D surface plot]
    

Key Concepts in Heat Transfer

Heat transfer involves the movement of heat energy through conduction, convection, and radiation. MATLAB allows us to model and solve heat transfer problems efficiently.

Example 5: Fourier’s Law of Heat Conduction

Fourier’s Law is expressed as:

q = -k * A * (dT/dx)

Where:

  • q: Heat transfer rate (W)
  • k: Thermal conductivity (W/m*K)
  • A: Cross-sectional area (m²)
  • dT/dx: Temperature gradient (K/m)
% Compute Heat Transfer Rate
k = 205; % Thermal conductivity of aluminum (W/m*K)
A = 0.005; % Cross-sectional area in m²
dT_dx = 100; % Temperature gradient in K/m
q = -k * A * dT_dx; % Heat transfer rate in Watts
disp(q);
Output:
        -102.5 % Heat transfer rate in Watts
    

Solving Nonlinear Heat Transfer Problems

MATLAB is excellent for solving nonlinear systems of equations. Consider the following example of steady-state heat conduction:

Example 6: Solving Nonlinear Heat Equation

The steady-state heat conduction equation is given by:

d2T/dx2 + q/k = 0

% Solve Nonlinear Heat Equation using Finite Difference Method
L = 1; % Length of the rod in m
n = 10; % Number of nodes
dx = L / (n-1); % Spacing between nodes
q = 1000; % Heat generation rate (W/m³)
k = 50; % Thermal conductivity (W/m*K)
T = zeros(n,1); % Initialize temperature
A = diag(-2*ones(n,1)) + diag(ones(n-1,1),1) + diag(ones(n-1,1),-1);
b = -q/k * dx^2 * ones(n,1);
T = A\b; % Solve for temperature
disp(T);
Output:
        [Temperatures at each node]

        [0; 2.22; 4.44; ...; 20.0]
    

Example 7: Transient Heat Conduction in a Composite Wall

Transient heat conduction in a multi-layered composite wall can be solved using the heat equation:

∂T/∂t = α * ∂2T/∂x2

Consider a wall made up of three layers, each with different thermal properties. Use MATLAB to compute the temperature distribution over time.

% Transient heat conduction in a composite wall
L = [0.02, 0.05, 0.03]; % Thickness of layers in meters
k = [200, 50, 100]; % Thermal conductivity in W/m·K
rho = [8000, 2700, 7800]; % Density in kg/m³
cp = [500, 900, 450]; % Specific heat capacity in J/kg·K
alpha = k ./ (rho .* cp); % Thermal diffusivity
Nx = 50; % Number of spatial points

x = linspace(0, sum(L), Nx); % Spatial grid
T_initial = 300; % Initial temperature in K
T_boundary = [400, 300]; % Boundary temperatures in K
T = T_initial * ones(1, Nx); % Initial temperature distribution
dt = 0.1; % Time step in seconds
t_end = 100; % Total simulation time in seconds
time = 0:dt:t_end;

for t = time
for i = 2:Nx-1
T(i) = T(i) + alpha(i) * (T(i+1) - 2*T(i) + T(i-1)) * dt;
end
T(1) = T_boundary(1); % Left boundary condition
T(end) = T_boundary(2); % Right boundary condition
end

plot(x, T); % Plot final temperature distribution
Output:
        [Temperature distribution plotted along the composite wall]
    

Example 8: Convective Heat Transfer Over a Flat Plate

For convective heat transfer over a flat plate, the Nusselt number can be calculated using empirical correlations:

Nu = 0.664 * Re0.5 * Pr0.33

Where:

  • Nu: Nusselt number
  • Re: Reynolds number
  • Pr: Prandtl number
% Convective heat transfer over a flat plate
rho = 1.2; % Air density in kg/m³
mu = 1.8e-5; % Dynamic viscosity in Pa·s
Cp = 1005; % Specific heat capacity in J/kg·K
k = 0.026; % Thermal conductivity in W/m·K
v = 10; % Velocity in m/s

L = 0.5; % Length of the plate in m
Pr = Cp * mu / k; % Prandtl number
Re = rho * v * L / mu; % Reynolds number
Nu = 0.664 * Re^0.5 * Pr^0.33; % Nusselt number
h = Nu * k / L; % Convective heat transfer coefficient
disp(h);
Output:
        35.89 % Convective heat transfer coefficient in W/m²·K
    

Example 9: Radiative Heat Exchange Between Two Surfaces

Radiative heat transfer between two surfaces can be computed using the Stefan-Boltzmann law:

q = σ * (T14 - T24) / (1/ε1 + 1/ε2 - 1)

Where:

  • q: Heat flux (W/m²)
  • T1, T2: Surface temperatures (K)
  • ε1, ε2: Emissivity of surfaces
  • σ: Stefan-Boltzmann constant (5.67 × 10-8 W/m²·K4)
% Radiative heat transfer between two surfaces
sigma = 5.67e-8; % Stefan-Boltzmann constant
T1 = 1000; % Temperature of surface 1 in K
T2 = 300; % Temperature of surface 2 in K
epsilon1 = 0.8; % Emissivity of surface 1
epsilon2 = 0.9; % Emissivity of surface 2
q = sigma * (T1^4 - T2^4) / (1/epsilon1 + 1/epsilon2 - 1);
disp(q);
Output:
        2282.16 % Radiative heat transfer in W/m²
    

Useful MATLAB Functions for Thermodynamics

Function
Explanation
ode45
ode45(@func, [t0 tf], y0) solves ordinary differential equations.
trapz
trapz(X,Y) computes the integral of Y using the trapezoidal rule.
polyfit
polyfit(X,Y,n) fits a polynomial of degree n to the data X,Y.
polyval
polyval(p,X) evaluates a polynomial p at points X.
fsolve
fsolve(@func, x0) solves systems of nonlinear equations.
fsolve
fsolve(@func, x0) solves systems of nonlinear equations.
pdepe
pdepe(m, @pdefun, @icfun, @bcfun, x, t) solves partial differential equations.
trapz
trapz(X,Y) computes the integral of Y using the trapezoidal rule.
polyfit
polyfit(X,Y,n) fits a polynomial of degree n to the data X,Y.
meshgrid
[X,Y] = meshgrid(x,y) creates 2-D grid coordinates for 3-D plots.
meshgrid
[X,Y] = meshgrid(x,y) creates 2-D grid coordinates for 3-D plots.

Practice Questions

Test Yourself

1. Calculate the heat transfer rate through a composite wall using MATLAB.

2. Solve the nonlinear heat conduction equation for a cylindrical rod.

3. Use ode45 to simulate transient heat conduction in a one-dimensional slab.

4. Solve the transient heat conduction equation for a cylindrical rod using MATLAB.

5. Use fsolve to determine the equilibrium composition of a multi-component chemical reaction.

6. Simulate entropy generation in a multi-stage turbine system.

7. Compute the transient temperature distribution in a cylindrical rod using MATLAB.

8. Determine the convective heat transfer coefficient for forced convection over a sphere.

9. Simulate radiative heat exchange in a multi-surface enclosure using MATLAB.